40s+2s=42s^2

Solution for 40s+2s=42s^2 equation:

40s+2s=42s^2

We move all terms to the left:

40s+2s-(42s^2)=0

determiningTheFunctionDomain
-42s^2+40s+2s=0

We add all the numbers together, and all the variables

-42s^2+42s=0

a = -42; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-42)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-42}=\frac{-84}{-84}
=1
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-42}=\frac{0}{-84}
=0
$